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In a rhombus ABCD, angle ACB=60. Find angle BAC angle DCA angle ADC

Answer»

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If ∠DAB=∠DCB=60°


This MEANS that DAB  and DCB are equilateral


so ∠ADB=60°


∠POB=θP=(√3/2 cosθ,√3/2sinθ)


A=(0,3–√)B=(1,0)C=(0,−3–√)D=(−1,0)


(Let O the center of the CIRCLE


and the radius of the circle is r=AOsin60°


=√3/2 and the distance


AO=√3


If there is any confusion PLEASE leave a comment below.


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