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In a resonance tube experiment, an 80 cm air column in resonance with a turning fork in first overtone. Which equation can represent correct pressure variation in the air column (x=0 is the top point of the tube, neglect end correction, speed of sound =320 m//sec)A. `A "sin" (15pi)/8xcos600pit`B. `A"cos"(15pi)/8xsin600pit`C. `A"cos"(15pi)/8 x sin300pit`D. `A"sin" (15pi)/ xsin300pit` |
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Answer» Correct Answer - A At the open end pressure node is present So that at `x=0` P should be zero and `v=flambda` for first over tone `(3lambda)/4 = 0.80` `Rightarrow f=300` `Rightarrow omega=2pif = 600t` Hence `P=A"sin"(15pi)/8xcos600t` |
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