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In a regular polygon of n sides, each corner is at a distance r from the centre. Identical charges of magnitude Q are placed at (n - 1) corners. The field at the centre is(a) k Q/r2(b) (n - 1) k Q/r2(c) n/ n - 1 k Q/r2(d) n - 1/ n k Q/r2 |
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Answer» Correct Answer is: (a) k Q/r2 If charges were placed at all the corners, the field at the centre would be zero. Hence, the field at the centre due to any one charge is equal (and opposite) to the field due to all the other (n - 1) charges. |
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