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In a region of uniform magnetic induction `B=10^(2)` tesla, a circular coil of radius `30 cm` and resistance `pi^(2)` ohm is rotated about an axis which is perpendicular to the directon of `B` and which form a diameter of the coil. If the coil rotates at `200rpm` the amplitude of the alternating current induced in the coil isA. `4pi^(2)mA`B. `30mA`C. `6mA`D. `200mA` |
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Answer» Correct Answer - C Amplitude of the current `I_(0)=(e_(0))/(R )=(omegaNBA)/(R )=(2pivNB(pir^(2)))/(R )` `i_(0)=(2pixx1xx10^(-2)xxpi(0.3)^(2))/(pi^(2))=6xx10^(-3)A=6mA` |
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