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In a rectangle ABCD, it's diagonal AC=15cm and angle ACD = alpha. if cot alpha=3/2, find perimeter and area of the rectangle. |
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Answer» Answer: The perimeter is 150/√13. Step-by-step explanation: LET's say if THETA is the angle between diagonal and the side of the rectangle then AB/BC = cot θ If cotθ = 3/2 then sinθ = 2/√13 Sin θ = BC/AC 2/√13 = BC / 15 BC = 30/ √ 13 Similarly COS θ = 3/√13 cos θ = AB/AC =AB/15 3/√ 15 =AB /15 so AB = 45/√13 So perimeter = 2(AB+ BC) = 2(30/√ 13 + 45/√ 13) = 150/√13
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