1.

In a reaction vessel, 0.184 g of NaOH is required to be added for completing the reaction. How many millilitres of 0.150 M NaOH solution should be added for this requirement?

Answer»


Solution :1000 ML of 0.150 M NaOH CONTAIN NaOH = 0.150 MOL `=0.150xx40=6g`
i.e., For 6 g in 0.150 M M NaOH solution, VOLUME of solution `-=" 1000 mL"`
`therefore"For 0.184 g in 0.150 M NaOH solution, volume "-=(1000)/(6)xx0.184=30.7mL`


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