In a quadrilateral ABCD,AO and BO are the bisectors of ∠A and ∠B r

1.	In a quadrilateral ABCD,AO and BO are the bisectors of ∠A and ∠B respectively, ∠C=70∘ and ∠D=30∘. Then, ∠AOB= ? (a) 40∘ (b) 50∘ (c) 80∘ (d) 100∘
Answer» In a quadrilateral $A B C D, A O$ and $B O$ are the bisectors of $∠ A a n d ∠ B$ respectively, $∠ C = 70^{\circ} a n d ∠ D = 30^{\circ}$ . Then, $∠ A O B =$ ? (a) $40^{\circ}$ (b) $50^{\circ}$ (c) $80^{\circ}$ (d) $100^{\circ}$

In a quadrilateral ABCD,AO and BO are the bisectors of ∠A and ∠B respectively, ∠C=70∘ and ∠D=30∘. Then, ∠AOB= ? (a) 40∘ (b) 50∘ (c) 80∘ (d) 100∘

Answer»

In a quadrilateral $A B C D, A O$ and $B O$ are the bisectors of $∠ A a n d ∠ B$ respectively, $∠ C = 70^{\circ} a n d ∠ D = 30^{\circ}$ . Then, $∠ A O B =$ ?

(a) $40^{\circ}$

(b) $50^{\circ}$

(d) $100^{\circ}$

Discussion

No Comment Found

Related InterviewSolutions

Given, tan(A+B)=√3 and tan(A−B)=1√3If B<A<90∘, then, find the values of A and B in degrees.
Represent -25.6875 in rational form.
Factorise:25x2 – 10x + 1 – 36y2
1.How many pairs of adjacent angles are formed when two lines intersect in a point?
if x=squareroot3 + 1 /2 then value of 4x^3 +2x^2-8x+7 is??
Question 1In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = RS and PA || QB || RC. Prove that ar (PQE) = ar (CFD).
Question 1(ii) Do the following pair of linear equations have no solution? Justify your answer. x = 2y and y = 2x
In a parallelogram ABCD, ∠D = 135°, determine the measures of ∠A and ∠B.
The value of (2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=
Number of real zero(s) of polynomial f(y) = ay2 + by + c, is

In a quadrilateral ABCD,AO and BO are the bisectors of ∠A and ∠B respectively, ∠C=70∘ and ∠D=30∘. Then, ∠AOB= ? (a) 40∘ (b) 50∘ (c) 80∘ (d) 100∘

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment