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In a quadrilateral ABCD, \angle A + \angle D = 90^°. Prove that AC^2+ BD^2 = AD^2 + BC^{ ^2} \lbrack Hint: Produce AB and DC to meet at E.\rbrack |
| Answer» In a quadrilateral ABCD, \angle A + \angle D = 90^°. Prove that AC^2+ BD^2 = AD^2 + BC^{ ^2} \lbrack Hint: Produce AB and DC to meet at E.\rbrack | |