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In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B =(a) 60°(b) 80°(c) 120°(d) None of these |
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Answer» In a quadrilateral ABCD, ∠A + ∠C is 2 times ∠B + ∠D. If ∠A = 140° and ∠D = 60°, then ∠B = (a) 60° (b) 80° (c) 120° (d) None of these |
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