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In a pure capacitive circuit if the frequency of ac source is doubled, then its capacitive reactance will beA. remains sameB. doubledC. halvedD. zero

Answer» Correct Answer - C
Capacitive reactance, `X_(C )=(1)/(2pi upsilon C)`
`rArr X_(C ) prop (1)/(upsilon) therefore (X_(C_(1)))/(X_(C_(2)))=(upsilon_(2))/(upsilon_(1))=(2upsilon)/(upsilon)=2`
`rArr X_(C_(2)) = (X_(C_(1)))/(2)`


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