In a process, temperature and Volume of 1 mole of an ideal monoatomic

1.	In a process, temperature and Volume of 1 mole of an ideal monoatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by ∆T. Amount of heat absorbed by gas is? 1) kR∆T/22) 2kR∆T/33) R∆T/24) 3kR∆T/2
Answer» Answer: 3) RΔT/2 Explanation: Firstly thanks for the nice question!! The process is described by VT=constant (K)---(2) Since this is no known ORDINARY process where a single ELEMENT is constant like adiabatic, ISOTHERMAL etc. ,This a polytropic process Since PV=RT =>T=PV/R---(1) From (1) and (2), PV²=constant WORK done by such a process is given by RΔT/(γ-1) Change in internal energy is given by fRΔT/2 Using ΔU=Q-W Q=ΔU+W =(3)RΔT/2 - RΔT/(2-1) Q= RΔT/2 [ NOTE : here W is negative due to work done on the gas] Hope this answer helped you :)

In a process, temperature and Volume of 1 mole of an ideal monoatomic gas are varied according to the relation VT=k where k is a constant. In this process, the temperature of gas is increased by ∆T. Amount of heat absorbed by gas is? 1) kR∆T/22) 2kR∆T/33) R∆T/24) 3kR∆T/2

Answer»

Answer:

3) RΔT/2

Explanation:

Firstly thanks for the nice question!!

The process is described by VT=constant (K)---(2)

Since this is no known ORDINARY process where a single ELEMENT is constant like adiabatic, ISOTHERMAL etc. ,This a polytropic process

Since PV=RT =>T=PV/R---(1)

From (1) and (2),

PV²=constant

WORK done by such a process is given by RΔT/(γ-1)

Change in internal energy is given by fRΔT/2

Using ΔU=Q-W

Q=ΔU+W =(3)RΔT/2 - RΔT/(2-1)

Q= RΔT/2

[ NOTE : here W is negative due to work done on the gas]

Hope this answer helped you :)

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