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In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process? |
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Answer» Heat absorbed by the system, (q) = + 701 J Work done by the system (w) = – 304 J Change in internal energy (∆U) = q + w = 701 – 394 = 307 J |
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