1.

In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

Answer»

Heat absorbed by the system, (q) = + 701 J

 Work done by the system (w) = – 304 J 

Change in internal energy (∆U) = q + w 

= 701 – 394 

= 307 J



Discussion

No Comment Found

Related InterviewSolutions