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In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length ofthe wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what isthe emf of the second cell ? |
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Answer» Solution :Here `epsi_1 = 1.25 V, l_1 = 35.0 CM " and" l_2 = 63.0 cm` If emf of the second cell be `epsi_2`, then `epsi_1/epsi_2= l_1/l_2` ` THEREFORE epsi_2 = epsi_1 .l_2/l_1 = (1.25 xx 63.0)/(35.0) = 2.25 V` |
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