1.

In a plane electromagnetic ware the electric field oscillates sinusoidally at frequency of 2.0xx10^10 Hz and amplitude 48Vm^(-1).What is wagelength of the wave ?

Answer»

Solution :Here `epsilon=48 Vm^(-1), f=2.0xx10^10 Hz C=3xx10^8 MS^(-1)` (i) Wavelength of the WAVE `lambda=C/f=(3xx10^8)/(2.0xx10^10) = 1.5xx10^(-2) m.`


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