In a pipe open at both ends, ‘n1’ and ‘n2’ be the frequencies

1.	In a pipe open at both ends, ‘n1’ and ‘n2’ be the frequencies corresponding to vibrating lengths ‘l1’ and ‘l2’ respectively. The end correction is
Answer» ANSWER: E = (L2 - 3L1)/2 Explanation: HOPE the answer will HELP you

In a pipe open at both ends, ‘n1’ and ‘n2’ be the frequencies corresponding to vibrating lengths ‘l1’ and ‘l2’ respectively. The end correction is

Answer»

ANSWER:

E = (L2 - 3L1)/2

Explanation:

HOPE the answer will HELP you

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In a pipe open at both ends, ‘n1’ and ‘n2’ be the frequencies corresponding to vibrating lengths ‘l1’ and ‘l2’ respectively. The end correction is

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