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In a particular system the units of length, mass and time are chosen to be `10 cm, 10 g` and `0.1 s` respectively. The unit of force in this system will be equal toA. 0.1NB. 1NC. 10 ND. 100N

Answer» `n_(1)u_(1)=n_(2)u_(2)`
`1[kg][m][sec]^(-2)=n_(2)[10gm][10cm][0.1sec]^(-2)`
`n_(2)=1[(1000gm)/(10gm)]^(1)[(100gm)/(10)]^(1)[(sec)/(0.1sec)]^(-2)`
`n_(2)=(1000)/(10^(4))=0.1N`


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