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In a parallelogram ABCD, two points and Q are taken on its diagonal BD such that DP = BQ. Prove that PQ and AC bisect each other. |
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Answer» ong>ANSWER: Here, ABCD is a parallelogram. AB∥DC and BD is a transversal. ∴ ∠ABQ=∠CDP [ Alternate angles ] ---- ( 1 ) In △AQB and △CPD, ⇒ AB=CD [ OPPOSITE SIDES of parallelogram are equal ] ⇒ ∠ABQ=∠CDP [ From ( 1 ) ] ⇒ BQ=DP [ Given ] ∴ △AQB≅△CPD [ By SAS CONGRUENCE ] ⇒ AQ=CP [ CPCT ] |
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