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In a parallel plate capacitor with air between the plates, each plate has an area of 6xx10^(-3)m^2and the distance between the plates is 3 m. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100V supply. What is the charge on the each plate of the capacitor? |
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Answer» Solution :Here `A = 6xx10^(-3) m^(2) , d = 3XX10^(-3), epsilon_(0) = 8.85 xx10^(-12) "Fm"^(-1) V = 100 V` we have `C = (epsilon_(0)A)/d` `= (8.85xx10^(-12) xx6xx10^(-3))/(3xx10^(-3))` `C = 17.7 xx10^(-12)F` The charge on each plate is EQUAL and OPPOSITE and the charge `Q = CV` `Q = 17.7 xx10^(-12) xx100` `= 17.7 xx10^(-10)C` `Q = 1.77 nC` |
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