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In a mixture of equal weights of h2 and he gases at pressure of 6 atm the partial pressure of helim is

Answer»

The partial pressure of HYDROGEN in the mixture of 1.22 atmExplanation:We know that partial pressure of a gas is the product of the “TOTAL pressure” and the CONCENTRATION or the “mole FRACTION of a gas” in the mixture.Partial pressure = Total pressure × Mole fractionLet the moles of each gas be X.We know that the atomic MASSES given below:So, we have the mole fraction of each gas which is given below:The total moles of the gas mixture Now, to calculate the partial pressure of :Partial pressure = Total pressure × Mole fractionPartial pressure = 1.22 atmRead more on Brainly.in - brainly.in/question/1467772#readmoreExplanation:The partial pressure of hydrogen in the mixture of 1.22 atmExplanation:



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