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In a meter bridge experiment, null point is obtained at `20 cm` from one end of the wire when resistance `X` is balanced against another resistance `Y`. If `X lt Y`, then the new position of the null point from the same end, if one decides to balance a resistance of `4 X` against `Y` will be at.A. 50 cmB. 80 cmC. 40 cmD. 70 cm |
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Answer» Correct Answer - A `(X)/(Y) = (20)/(100 - 20) rArr 4 X = Y` `(4 X)/(Y) = (l)/(100 -l) rArr 1 = (l)/(100 - l)` `l = 50 cm`. |
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