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In a laboratory, A container has pure acid. From this container, 10 L of acid was taken out and replaced by water. The process was further repeated thrice. The volume of acid in the container at the end, if the container had 100 L of the pure acid initially, is1. 58.23 L2. 63.23 L3. 78.32 L4. 65.61 L5. 72.93 L |
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Answer» Correct Answer - Option 4 : 65.61 L Given: Total acid = 100 L Taken out acid and replaced by water = 10 L Repeated process = 4 times Concept Used: The final volume of acid = Total acid[1 - (Taken out and replaced/Total acid)]n times repeated n = Number of repeated process Calculation: The volume of remaining acid = Total acid[1 - (Taken out and replaced/Total acid)]n times repeated The volume of remaining acid = 100(1 - 10/100)4 ⇒ 100(1 - 1/10)4 ⇒ (100 × 9 × 9 × 9 × 9)/(10 × 10 × 10 × 10) ⇒ 6561/100 ⇒ 65.61 L ∴ The volume of remaining milk is 65.61 L |
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