In a hydraulic press, an effort of 50N Is applied to the piston to raise a load of 500N. If this effort piston has an area of 5 cm2, what is the area of the load piston?

In a hydraulic press, an effort of 50N Is applied to the piston to rai

1.	In a hydraulic press, an effort of 50N Is applied to the piston to raise a load of 500N. If this effort piston has an area of 5 cm2, what is the area of the load piston?
Answer» - PASCAL'S LAW CONCEPT :- The fluid pressure is transmitted equally in all direction.FORMULAF1/A1 = F2/A2. (F1 - effort piston , F2 - load piston)SOLUTIONSGiven,F1 = 50 N F2 = 500 N.A1 = 5 cm²A2 = ?Applying the formula F1/A1 = F2/A2= > 50/5 = 500/A2°> A2 = 50 cm² HENCE, AREA of load piston is 50 cm².

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In a hydraulic press, an effort of 50N Is applied to the piston to raise a load of 500N. If this effort piston has an area of 5 cm2, what is the area of the load piston?

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