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In a hydraulic machine, a force of 4N is applied to the piston of the area 2pof cross-section 10 square centimetre. The force applied on its piston ofthe area of cross-section 100 square centimetre is20 n30 nor 40 n |
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Answer» Answer: We KNOW that, PRESSURE= Force/Area ⇒Pressure= 2/10 = 0.2 cm^-2 =0.2Ncm ^−2 Now, Pressure=0.2 Again, Force=Pressure×Area Force=0.2×100=20N Hence your answer is 20 N |
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