1.

In a hydraulic lift, used at a service station the radius of the large and small piston are in the ration of `20 : 1`. What weight placed on the small piston will be sufficient to lift a car of mass `1500 kg` ?A. `3.75` kgB. `37.5` kgC. `7.5` kgD. `75` kg

Answer» Correct Answer - A
`(m_(1)g)/(A_(1)) = (m_(2)g)/(A_(2))`
Solving. `m_(2) = 3.75 kg`.


Discussion

No Comment Found

Related InterviewSolutions