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In a house 15 Bulbs of 45 W, 15 bulbs of 100 W, 15 bulbs of 10 W and Two heaters of 1 KW each is connected to 220 V Mains supply then find minimum fuse current(1) 5 A (2) 20 A (3) 25 A (4) 15 A |
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Answer» Answer is (2) 20 A Total power is (15 × 45) + (15 × 100) + (15 × 10) + (2 × 1000) = 4325 W So current is = 4325/220 19.66 A |
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