In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunc

1.	In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ? (a) 20 (b) 24 (c) 26 (d) 28
Answer» (b) 24 Number of people having either or both type of lunches = \(\frac{60}{100}\) x 96 + \(\frac{30}{100}\) x 96 - \(\frac{15}{100}\) x 96 = \(\frac{75\times96}{100}\) = 72 Number of people who did not eat either type of lunch = 96 – 72 = 24

In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both types of lunch. If 96 people were present, how many did not eat either type of lunch ? (a) 20 (b) 24 (c) 26 (d) 28

Answer»

(b) 24

Number of people having either or both type of lunches

= \(\frac{60}{100}\) x 96 + \(\frac{30}{100}\) x 96 - \(\frac{15}{100}\) x 96 = \(\frac{75\times96}{100}\) = 72

Number of people who did not eat either type of lunch = 96 – 72 = 24