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In a GP of `7` terms, the last term is `(64)/(81)` and the common ratio is `(2)/(3)`. Find the 3rth term.A. 4B. 9C. 8D. 12 |
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Answer» Correct Answer - A Let `a` be the first term and r the common ratio of the GP. `T_y = ar^(6) = (64)/(81) rArr a =9` Therefore the 3rd term, `T_3 = ar^(2)` `T_3 = 9((2)/(3))^(2) =4`. |
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