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in a given species of tobacco there is 0.1mg of virus per c.c.the mass of virus is 4x10000000 kg per kilomole.the number of the molecules of virus present in 1 c.c. will be? plz explain with solution |
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Answer» virus = 4×10⁷ kg per kilomoleso mass of 1000 moles virus = 4×10⁷ kgso mass of 1 MOLE virus = 4×10⁷/1000 = 4×10⁴ kgmass of virus in 1CC tobacco, = 0.1mg0.1mg = 1×10⁻⁷ kg4×10⁴ kg contains 1 mole of virus1 kg will have = 1×10⁻⁷ kg will have = number of viruses in 1 mole = 6.022×10²³ virusesnumber of viruses in mole = So number of viruses PRESENT in 1 cc will be 1.505×10¹². |
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