In a G.P, the 3rd term is 24 and the 6th term is 192. Find the 10th te

1.	In a G.P, the 3rd term is 24 and the 6th term is 192. Find the 10th terma
Answer» We know that an = ar^n-1 Given that 3rd term is 24 a3 = ar^2 = 24 ---- (1) Given that 6th term is 192a6 = ar^5 = 192 --- (2) On dividing (2) by (1), we getr^3 = 8r = 2 --- (3) Substitute (3) in (1), we geta * (2)^2 = 244a = 24a = 6 The 10th term a10 = 6 * (2)^9 = 3072

In a G.P, the 3rd term is 24 and the 6th term is 192. Find the 10th terma

Answer»

We know that an = ar^n-1

Given that 3rd term is 24 a3 = ar^2 = 24 ---- (1)

Given that 6th term is 192a6 = ar^5 = 192 --- (2)

On dividing (2) by (1), we getr^3 = 8r = 2 --- (3)

Substitute (3) in (1), we geta * (2)^2 = 244a = 24a = 6

The 10th term a10 = 6 * (2)^9 = 3072