1.

in a frequency distribution, the mid value of class 27.5 and the width of the class is 5. find the upper limit​

Answer»

Answer:

given,

(UPPER LIMIT+LOWER limit)/2=27.5

Upper limit+Lower limit=2×27.5=55•••eq.1

Also,

Upper Limit - Lower limit=class width=5•••eq.2

On ADDING eq.2 AMD eq.1,we get:

Upper limit+lower limit+upper limit-lower limit=55+5

2Upper limit=60

So,Upper limit=30.


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