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In a experiment refractive index of glass is measured and following values are obtained - 1.32,1.4,1.31,1.29,1.33,1.3. Find its mean value, absolute value,relative error and percentage error.​

Answer»

Explanation:Given values ⇒1.29 1.33 1.34 1.35 1.32 1.36 1.30 and 1.33Now, there are TOTAL of the 8 term.Mean value = Sum of all theobservations/No. of observations.:: Mean value = (1.29 + 1.33 + 1.34 +1.35 +1.32 +1.36 +1.30 + 1.33)/8= 10.62/8= 1.3275= 1.33Now, for ABSOLUTE ERROR in each term,X₁11.33- 1.291 = 0.04X₂ = 11.33 -1.33/ = 0.00X3 = 11.33 1.34/= 0.01X4 11.33 1.35/= 0.02Xs = /1.33 - 132| = 0.01X6 = 11.33 1.36/= 0.03X7 = 11.33 1.30l = 0.03Xg = 11.33 1.33/ = 0.00.: Mean Absolute error = (0.04 + 0.00 + 0.01 +0.02 +0.01 +0.03 +0.03 +0.00)/8:: Mean Absolute error = (0.04 + 0.00 +0.01 +0.02 +0.01 + 0.03 +0.03 + 0.00)/8= 0.14/8= 0.0175= 0.018Vol 49.: Relative Error = Mean absolute error/ Mean Value= 0.018/1.33= 0.135= 0.12:: % Error = 0.12 × 100% Error = 12%Hope it helps. :-)



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