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In a diode detector , output circuit consists of ` R = 1 M omega and C = 1 pF`. Calculate the carrier frequency it can detect. |
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Answer» Correct Answer - `v_(c) > > 1 MHz` Here , `RC = 10^(6) xx 10^(-12) = 10^(-6) s` For demodulation , `(1)/( v_( c )) lt lt RC or v_( c ) gt gt 1//RC` ` v_( c ) gt gt (1)/( 10^(-6)) = 10^(6) Hz = 1 MHz` ` :. v_( c ) gt gt 1 MHz` |
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