1.

In a diffraction pattern due to a single slit of width 'a' the first minimum is observed at an angle 30 when light of wavelength 5000 Å is incident on the slit. The first secodary maximum is observed at an angle of :

Answer»

`SIN^(-1)(2/3)`
`sin^(-1) (1/2)`
`sin^(-1)(3/4)`
`sin^(-1)(1/4)`

SOLUTION :The condition for the FIRST minima is given by
`sin 30^@ = lambda/a = 1/2 ""…(i)`
The condition for the second minima
` sin THETA= (3 lambda)/(2a) = 3/2(1/2) implies theta = sin^(-1) 3/4`.


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