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In a diffraction pattern due to a single slit of width 'a' the first minimum is observed at an angle 30 when light of wavelength 5000 Å is incident on the slit. The first secodary maximum is observed at an angle of : |
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Answer» `SIN^(-1)(2/3)` `sin 30^@ = lambda/a = 1/2 ""…(i)` The condition for the second minima ` sin THETA= (3 lambda)/(2a) = 3/2(1/2) implies theta = sin^(-1) 3/4`. |
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