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In a different planet, the acceleration due to gravity is `2m//s^(2)`. A particle is thrown horizontally at a speed of `3 m//s` from a height of `10 m`. The equation of trajectory of the particle comes out to be `x^(2)=alphay`. Find the value of `alpha` [Take `+X-`axis alonf the direction of projection and `+Y` axis towards the surface of planet.]A. `7`B. `8`C. `9`D. `10`

Answer» Correct Answer - C
`x=3t`
`y=t^(2)rArr x^(2)=9y`.


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