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In a detector, output circuit consists of `R = 10kOmega and C = 100 p F.` Calculate the frequency of carrier signal it can detect. |
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Answer» Here, `R = 10kOmega = 10^4Omega` `C = 100 p F = 10^(-10) F` Time constant of the circuit `tau = RC = 10^4 xx 10^(-10) = 10^(-6)`s For demodulation, the condition is `1/v_C lt lt RC or v_c gt gt 1/(RC)` i.e., `v_c gt gt 1/10^(-6) = 10^(6) Hz` `:.` Frequency of carrier signal must be much greater than `10^6 Hz or 1 MHz.` |
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