In a ΔABC, the sides BC=5,CA=4,AB=3. If A(0,0) and the internal bisector of angle A meets BC in D(127,127), then incentre of △ABC is

In a ΔABC, the sides BC=5,CA=4,AB=3. If A(0,0) and the internal bisec

1.	In a ΔABC, the sides BC=5,CA=4,AB=3. If A(0,0) and the internal bisector of angle A meets BC in D(127,127), then incentre of △ABC is
Answer» In a $Δ A B C,$ the sides $B C = 5, C A = 4, A B = 3 .$ If $A (0, 0)$ and the internal bisector of angle $A$ meets $B C$ in $D (\frac{12}{7}, \frac{12}{7})$ , then incentre of $△ A B C$ is