1.

In a ΔABC, 11+tan2A2+11+tan2B2+11+tan2C2=k[1+sinA2sinB2sinC2], then the value of k is

Answer» In a ΔABC, 11+tan2A2+11+tan2B2+11+tan2C2=k[1+sinA2sinB2sinC2], then the value of k is


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