In a Δ ABC, the internal bisector of angle A meets opposite side BC at point D. Through vertex C, line CE is drawn parallel to DA which meets BA produced at point E. Show that Δ ACE is isosceles.

In a Δ ABC, the internal bisector of angle A meets opposite side BC a

1.	In a Δ ABC, the internal bisector of angle A meets opposite side BC at point D. Through vertex C, line CE is drawn parallel to DA which meets BA produced at point E. Show that Δ ACE is isosceles.
Answer» In a $Δ$ ABC, the internal bisector of angle A meets opposite side BC at point D. Through vertex C, line CE is drawn parallel to DA which meets BA produced at point E. Show that $Δ$ ACE is isosceles.