In a cyclic quadrilateral ABCD, if (∠B−∠D)=60∘, show that the smaller of the two is 60∘.

In a cyclic quadrilateral ABCD, if (∠B−∠D)=60∘, show that the

1.	In a cyclic quadrilateral ABCD, if (∠B−∠D)=60∘, show that the smaller of the two is 60∘.
Answer» In a cyclic quadrilateral ABCD, if $(∠ B - ∠ D) = 60^{\circ}$ , show that the smaller of the two is $60^{\circ}$ .