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In a communication system, operating at 1200 mm, only 2% of the source frequency is available for T.V. transmission , having a bandwidth of 5 MHz. The number of T.V. channels that can be transmitted isA. 1 millionB. 2 millionC. 0.5 millionD. 0.1 million |
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Answer» Correct Answer - A Frequency of the source `=c/lambda=(3xx10^8)/(1200xx10^(-9)) =(3xx10^8xx10^7)/12 = 25 xx 10^13` Hz Available band width for T.V. Transmission `=2/100xx25xx10^13=5xx10^12` Hz `therefore` No. of T.V. channels =` "Total bandwidth"/"Bandwidth per channel"=(5xx10^12)/(5xx10^6)=10^6`=1 million |
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