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In a class, the highest score is 91. If the highest score is twice thelowest score plus 11, find the lowest score. |
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Answer» Answer: The lowest score of the exam was 40.Step-by-step explanation: It is PROVIDED that the highest score is twice the lowest score PLUS 11. The STATEMENT can be expressed as follows: Highest score = (2 × Lowest score) + 11 91 = (2 × Lowest score) + 11 (2 × Lowest score) = 91 - 11 Lowest score = 80/2 = 40 Thus, the lowest score of the exam was 40. |
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