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In a circuit `L, C` and `R` are connected in series with an alternating voltage source of frequency `f`. The current lead the voltages by `45^(@)`. The value of `C` is :A. `1/(2pif(2pifL+R))`B. `1/(pif(2pifL+R))`C. `1/(2pif(2pifL-R))`D. `1/(pif(2pifL-R))` |
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Answer» Correct Answer - C `therefore tanphi = (omegaL-1/(omegaC))/R` `phi` being the angle by which the current leads the voltage, Given, `phi=45^(@)` `therefore tan45^(@)=(omegaL-1/(omegaC))/R` `R=omegaL-1/(omegaC) rArr = 1/(omegaL-R)` `rArr C=1/(omega(omegaL-R)) = 1/(2pif(2pifL-R))`- |
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