Saved Bookmarks
| 1. |
In a circuit containing internal resistane r. Find the power delivered. |
|
Answer» Solution :(i) DUE to this internal RESISTANCE, the power delivered to the circuit is not equal to power RATING mentioned in the battery. (ii) For a battery of emf `xi` with an internal resistance r, the power delivered to the circuit of resistance R is given by `P= I xi=I(V+Ir)` Here Vis the voltage drop acrossthe resistane Randit is equal to IR. Therefore `P=I(IR+r)` `P=I^(2)R+I^(2)r` (iiii) Here `I^(2)` r is the power delivered to the internal resistane and `I^(2)` R is the power delivered to the electrical device (here it is the resistance R). For a good battery, theinternal resistance r is very SMALL, then `I^(2) r lt lt I^(2)` and almost ENTIRE power is delivered to the resistance. |
|