In a circle with radius 41cm,two equal chords are at adistance of 9cm

1.	In a circle with radius 41cm,two equal chords are at adistance of 9cm from thecentre. Find the lengths of thechord.
Answer» Answer: LENGTH of chord = 80cm Step-by-step explanation: radius of CIRCLE = 41cm distance between the centre and the chord = 9cm By using PYTHAGORAS theorem, we get 41^2 - 9^2 = BASE^ 2 1681 - 81 = base^2 1600 = base^2 base = 40cm therefore length of chord = 2 x 40 = 80 cm

In a circle with radius 41cm,two equal chords are at adistance of 9cm from thecentre. Find the lengths of thechord.

Answer»

Answer:

LENGTH of chord = 80cm

Step-by-step explanation:

radius of CIRCLE = 41cm

distance between the centre and the chord = 9cm

By using PYTHAGORAS theorem, we get

41^2 - 9^2 = BASE^ 2

1681 - 81 = base^2

1600 = base^2

base = 40cm

therefore length of chord = 2 x 40

= 80 cm

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In a circle with radius 41cm,two equal chords are at adistance of 9cm from thecentre. Find the lengths of thechord. ​

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In a circle with radius 41cm,two equal chords are at adistance of 9cm from thecentre. Find the lengths of thechord.