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In a circle with centre O. Chords PQ and RS intersect at right angles at point A inside the circle. Prove that ​​​​​​PQ2 + RS2 = 4[2PO2 - OA2] .

Answer» In a circle with centre O. Chords PQ and RS intersect at right angles at point A inside the circle. Prove that ​​​​​​PQ2 + RS2 = 4[2PO2 - OA2] .


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