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In a circle of radius 5 cm, AB and AC are two chords such that AB AC6 cm. Find the length of the chord BC. |
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Answer» See the diagram.we need to find 2y. In the right angled triangle AMC6² = x² + y²⇒ y² = 36-x² In the right angled triangle OMC5² = y² + (5-x)²⇒ 25 = (36-x²) + 25 + x² - 10x⇒ 25 = 36 - x²+ 25 + x² - 10x⇒ 0 = 36 - 10x⇒ x = 36/10 = 3.6 y =√(36-3.6²) =√23.04 = 4.8 cmBC = 2y = 4.8×2 = 9.6 cm |
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