In a circle of radius 12 cm, a chord subtends an angle of 120° at the

1.	In a circle of radius 12 cm, a chord subtends an angle of 120° at the centre. Find thearea of the corresponding minor segment of the circle (use π =3.14 and 13 = 1.732)
Answer» EXPERT Answer: DRAW OM AB in figure (RHS congruence) AOM=BOM BOM = (cpct) In OMA cos 60o = OM = 6 cm and sin 60o = AM = 6 cm ar AOB = AB OM = AM OM = 36 cm2 AREA of segment AXB = area of sector OAXB - ar AOB = 3.14 12 12 - 36 = (150.72 - 36) cm2 = 88.36 cm2

In a circle of radius 12 cm, a chord subtends an angle of 120° at the centre. Find thearea of the corresponding minor segment of the circle (use π =3.14 and 13 = 1.732)

Answer»

EXPERT Answer:

DRAW OM AB in figure

(RHS congruence)

AOM=BOM

BOM = (cpct)

In OMA

cos 60o =

OM = 6 cm

and sin 60o =

AM = 6 cm

ar AOB = AB OM = AM OM = 36 cm2

AREA of segment AXB

= area of sector OAXB - ar AOB

= 3.14 12 12 - 36

= (150.72 - 36) cm2

= 88.36 cm2

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In a circle of radius 12 cm, a chord subtends an angle of 120° at the centre. Find thearea of the corresponding minor segment of the circle (use π =3.14 and 13 = 1.732)​

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In a circle of radius 12 cm, a chord subtends an angle of 120° at the centre. Find thearea of the corresponding minor segment of the circle (use π =3.14 and 13 = 1.732)