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In a circle of diameter 40 cm the length of a chord is 20 cm find the length of minor arc of the chord |
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Answer» Step-by-step explanation: ∴ Radius (r) of the circle = 2 40
=20 cm Let AB be a chord (length = 20 cm) of the circle. In △OAB, OA = OB = Radius of circle = 20 cm Also, AB = 20 cm Thus, △OAB is an equilateral triangle. ∴θ=60 ∘ = 3 π
We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ= r l
∴ 3 π
= 20 arc AB
⟹arc AB= 3 20
π cm hope it helps plzz mark as brainliest |
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