1.

In a children's park, using the park ride the visitors can be made to rotate in a vertical circle. At the top of the circle a rider has an effective weight of magnitude 1000 N. If his actual weight is 500 N (i) What is his effective weight at the bottom of the cricle ? (ii) What is the effective weight when the rider is halfway to the centre of the circle ?

Answer»

Solution :`W_("top") = mromega^(2) - MG = 1000, mromega^(2) = 1000 + 500 = 1500 N, W_("bottom") = mromega^(2) + mg= 1500 + 500 = 2000 N`. Weight at half way = `mromega^(2) + mg cos theta = 1500 + 500 XX cos 45^(@) = 1586 N`


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