In a certain oscillatory system, the amplitude ofmotion is 5 m and the

1.	In a certain oscillatory system, the amplitude ofmotion is 5 m and the time period is 4 s. The timetaken by the particle for passing between pointswhich are at distances of 4 m and 2 m from thecentre and on the same side of it will be(a) 0.30 s (b) 0.32 s (c) 0.33 s (d) 0.35 s
Answer» Answer: C)0.33s Explanation: The equation for POSITION of particle at TIME 't' is given by x=(A)sin(ωt) ω=2π/T ,where T is time PERIOD =2π/4 =π/2 4=5sin(πt/2) =>t=(53⁰)2/π=(0.92)(2)/π=0.58s similarly; 2=5sin(πt/2) t=(0.41)(2)/π =0.26s the particle is at 4m and 2m when t₁=0.58s and t₂=0.26s ∴ time interval is given by t₁-t₂=0.3248=0.33 (APPROX) Hope this answer helped you, if so please mark brainliest :)

In a certain oscillatory system, the amplitude ofmotion is 5 m and the time period is 4 s. The timetaken by the particle for passing between pointswhich are at distances of 4 m and 2 m from thecentre and on the same side of it will be(a) 0.30 s (b) 0.32 s (c) 0.33 s (d) 0.35 s

Answer»

Answer:

C)0.33s

Explanation:

The equation for POSITION of particle at TIME 't' is given by x=(A)sin(ωt)

ω=2π/T ,where T is time PERIOD

=2π/4

=π/2

4=5sin(πt/2)

=>t=(53⁰)2/π=(0.92)(2)/π=0.58s

similarly;

2=5sin(πt/2)

t=(0.41)(2)/π =0.26s

the particle is at 4m and 2m when t₁=0.58s and t₂=0.26s

∴ time interval is given by t₁-t₂=0.3248=0.33 (APPROX)

Hope this answer helped you, if so please mark brainliest :)

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In a certain oscillatory system, the amplitude ofmotion is 5 m and the time period is 4 s. The timetaken by the particle for passing between pointswhich are at distances of 4 m and 2 m from thecentre and on the same side of it will be(a) 0.30 s (b) 0.32 s (c) 0.33 s (d) 0.35 s​

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In a certain oscillatory system, the amplitude ofmotion is 5 m and the time period is 4 s. The timetaken by the particle for passing between pointswhich are at distances of 4 m and 2 m from thecentre and on the same side of it will be(a) 0.30 s (b) 0.32 s (c) 0.33 s (d) 0.35 s